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Does fibrillation of survodutide at 2–8 °C show up as a loss of content or of purity?

Asked 20 Aug 2024Modified 19 months agoViewed 13k times
21

For reference: fibrillation · survodutide · 2–8 °C.

I would like the mechanism, because I want to be able to reason about the cases nobody has written about.

I have tried to reason it out from first principles and got to two contradictory conclusions.

So what is the mechanism, and how well established is it?

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askedbufferline4230k13820 Aug 2024

2 Answers

Accepted answer first, then by votes
105

Accepted answer

At 2–8 °C it can show up as either, and which one depends entirely on whether the product still elutes under the main peak. Purity is a ratio of areas, so a degradant only costs purity if the method resolves it. Content is a mass against a standard, so a degradant costs content whenever the parent is consumed — resolved or not. Ordered beta-sheet assembly, effectively irreversible, and its endpoint is opalescence you can see rather than a peak you can integrate. That is why the two measurements are not interchangeable and why an unchanged purity figure after an excursion to 2–8 °C is weak evidence: the method may simply be integrating the degradant along with the parent and reporting the sum as one peak.

The short version: water enables most of it, oxygen enables oxidation, surfaces enable adsorption, and agitation enables aggregation.

Hydrolysis cleaves the backbone, most readily at aspartate-proline and aspartate-glycine sequences, and is acid-catalysed. In a dry solid it barely proceeds at all.

Degradation pathway by condition

PathwayDominant whenDetected by
DeamidationSolution, neutral to alkaline pHRP-HPLC, +1 Da on MS
OxidationLight, trace metals, peroxidesRP-HPLC, +16 Da on MS
HydrolysisSolution, extremes of pHRP-HPLC, fragment masses
AggregationAgitation, interfaces, high concentrationSEC, visual haze; often invisible on RP-HPLC
Freeze-concentration damageFreeze-thaw of buffered solutionSEC, loss of recovered content

More usefully, oxidation targets methionine, cysteine and tryptophan, adding sixteen daltons per oxygen. It is catalysed by trace metals and promoted by dissolved oxygen and by light.

Deamidation via the succinimide intermediate is well characterised, with sequence-dependent rates highest for asparagine-glycine motifs.

At dilute concentrations, suspect adsorption before you suspect chemistry.

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answered · acceptedkwn_analytical147k35820 Nov 2024
3Does the same reasoning apply to material already in solution, or is that a different curve? – wren_calloway 2 months ago
4Thank you — this is the answer I was looking for. – Dr_Wren_Halliday 3 months ago
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91

Answering this needs the physical state, since a dry powder is protected from most of these and a solution is protected from none.

Deamidation converts asparagine or glutamine to the corresponding acid via a succinimide intermediate, adding one dalton. It is base-catalysed, accelerates above neutral pH and is the dominant aqueous pathway for many peptides.

Adsorption onto glass and plastic is significant at low concentrations — micrograms per millilitre — and negligible at milligrams per millilitre. It is the usual explanation for an apparent loss in a dilute preparation.

Adsorption losses at low concentrations are quantified in formulation studies and are the reason carrier proteins are used in dilute preparations.

A mass spectrum names the pathway. Plus one, plus sixteen, minus eighteen.

edited 26 Dec 2024 by RP_C18 — added the placebo-arm figures

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answeredRP_C18105k3481 Dec 2024
4Confirming that opening a cold vial in a humid room is a genuinely bad idea. – Dr_Bram_Verhoeven 8 months ago
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