Accepted answer
98.2 per cent is a statement about area, and the other 1.8 per cent is everything the detector saw and did not assign to your peak. Read it as 98.2 of every 100 units of peak area at whatever wavelength was used, not as 98.2 per cent of the mass in the vial. With the batch certificate attached you can at least see how the figure was produced, which is the difference between a measurement and a claim. What it still does not tell you is content: how many milligrams are actually there.
In practice, understanding purity requires separating the chemistry from the method from the reporting convention, and the three are not independent.
Column pore size affects mass transfer — a 100 Angstrom packing on a 5 kDa peptide restricts diffusion, broadening the peak and potentially hiding small impurities in the shoulders.
Reconciling gross mass to label claim
| Component | Typical share | Counted in purity? | Counted in content? |
|---|
| Target peptide | 88–94 % | Yes, as main peak | Yes |
| Related impurities | 1–3 % | Yes, as other peaks | No |
| Counter-ion (TFA or acetate) | 2–8 % | No | No |
| Residual water | 2–6 % | No | No |
| Bulking agent, if present | 0–40 % | No | No |
It helps to be literal here: the fraction of your main peak that is actually your target versus isomers, fragments or related sequences is invisible without complementary identity testing.
Published side-by-side method comparisons show that a two-point difference in purity on the same vial is easily explained by method choice alone.
The limitation is that single-digit micro-impurities become invisible at typical reporting thresholds, so "no impurities detected" means "none above one in two thousand."
Compare purity within a single laboratory on the same method, never across laboratories.
edited 25 May 2026 by n_takahashi — added the citation requested in comments