PeptideStack
5.2kquestions
20kanswers
220users

What happens to ecnoglutide after twelve weeks at 2–8 °C in solution?

Asked 25 Aug 2024Modified 20 months agoViewed 14k times
2

Concretely: ecnoglutide · twelve weeks · 2–8 °C.

This is one of those things that everyone repeats and nobody derives.

This matters practically, not just academically, because it changes what I would do next.

Is the standard explanation correct, and if so, what is the evidence for it?

peptide-stability
peptide-stability

The chemistry of peptide degradation: deamidation, oxidation, hydrolysis, aggregation and fibrillation, and how temperature, pH, ionic strength,…

908 questions
storage
storage

Storage conditions and their evidence base: minus twenty degrees for powder, refrigerated for solution, protection from light, and what the…

701 questions
shelf-life
shelf-life

How long a preparation remains within specification: labelled expiry for a sealed lyophilised vial, beyond-use dating after reconstitution, and…

327 questions
ecnoglutide
ecnoglutide

A long-acting GLP-1 receptor agonist with a cAMP-biased signalling profile. A niche tag, mostly used for mechanism questions about biased agonism…

223 questions
shareeditfollowflag
YM
askedyuki_morishita10k1425 Aug 2024

3 Answers

Accepted answer first, then by votes
123

Accepted answer

twelve weeks is 84 days, which at 2–8 °C is on the order of 84 refrigerated days. 2–8 °C is the condition the rule of thumb is anchored to, so it is the baseline rather than a multiplier: everything else in this thread is quoted relative to it. In solution the routes that matter are hydrolysis of the backbone, deamidation at Asn, and physical association — the first two cost content, the third costs neither until it precipitates. Over 84 days at 2–8 °C you should expect all three to have moved, and a purity figure to have noticed only some of them. Reconstituted material has no certificate; the one in the box describes the powder.

Start with the sequence, because which pathways are available depends on which residues are present.

Adsorption onto glass and plastic is significant at low concentrations — micrograms per millilitre — and negligible at milligrams per millilitre. It is the usual explanation for an apparent loss in a dilute preparation.

The underlying point is that hydrolysis cleaves the backbone, most readily at aspartate-proline and aspartate-glycine sequences, and is acid-catalysed. In a dry solid it barely proceeds at all.

Metal-catalysed oxidation of methionine is documented across peptide and protein formulations and is why chelators appear in some formulations.

Sequence determines which pathways apply, so general statements are general.

Swirl, never shake. Aggregation is a handling problem more than a time problem.

edited 14 Nov 2024 by lyoph_cake — fixed an arithmetic slip in the third paragraph

shareimprove this answerflag
LC
answered · acceptedlyoph_cake78k26729 Oct 2024
Sponsored

Sigma-Aldrich - Certified Reference Materials

Analytical standards and reagents with traceable certificates. Every quantitative result you read inherits the accuracy of the standard behind it.

Shop standards
48

Answer first: the degradation pathways worth knowing are hydrolysis, deamidation, oxidation, aggregation and adsorption, and each has a different trigger and a different mitigation.

Aggregation is physical: peptides unfold at air-liquid interfaces and associate. Shaking maximises that interface, which is why swirling and shaking produce visibly different outcomes on the same vial.

Freeze-thaw cycling drives aggregation through concentration at the ice interface and pH shifts as buffer components crystallise out at different rates. Each cycle costs something.

Adsorption losses at low concentrations are quantified in formulation studies and are the reason carrier proteins are used in dilute preparations.

Cold, dry, dark, still. Those four words cover most of the mitigation.

shareimprove this answerflag
CI
answeredcake_intact17k279 Nov 2024
35

Answering this needs the physical state, since a dry powder is protected from most of these and a solution is protected from none.

Oxidation targets methionine, cysteine and tryptophan, adding sixteen daltons per oxygen. It is catalysed by trace metals and promoted by dissolved oxygen and by light.

A mass spectrum resolves most of this: minus eighteen is dehydration or succinimide, plus one is deamidation, plus sixteen is oxidation, and an unchanged mass with a shifted retention time is an isomer.

Deamidation via the succinimide intermediate is well characterised, with sequence-dependent rates highest for asparagine-glycine motifs.

A mass spectrum names the pathway. Plus one, plus sixteen, minus eighteen.

shareimprove this answerflag
CO
answeredcoldbox941k1386 Oct 2024
8Does the same reasoning apply to material already in solution, or is that a different curve? – Dr_Ilse_Vandenberg 8 months ago
The desiccant point is under-appreciated and costs nothing to act on. – esther_vandeVelde 4 days ago
add a comment

Your answer

Ask PeptideStack is a static archive. Posting is closed, but the norms are worth stating: answer the question that was asked, show your working, cite the trial or the certificate, and say plainly where the evidence runs out.

Not medical advice. Research-use-only compounds are not approved for human use.