Accepted answer
At minus 20 °C it can show up as either, and which one depends entirely on whether the product still elutes under the main peak. Purity is a ratio of areas, so a degradant only costs purity if the method resolves it. Content is a mass against a standard, so a degradant costs content whenever the parent is consumed — resolved or not. Met and Trp take up oxygen sixteen daltons at a time, and the oxidised species is more polar, so on a reversed-phase column it elutes ahead of the parent rather than behind it. That is why the two measurements are not interchangeable and why an unchanged purity figure after an excursion to minus 20 °C is weak evidence: the method may simply be integrating the degradant along with the parent and reporting the sum as one peak.
Answering this needs the physical state, since a dry powder is protected from most of these and a solution is protected from none.
Oxidation targets methionine, cysteine and tryptophan, adding sixteen daltons per oxygen. It is catalysed by trace metals and promoted by dissolved oxygen and by light.
The underlying point is that hydrolysis cleaves the backbone, most readily at aspartate-proline and aspartate-glycine sequences, and is acid-catalysed. In a dry solid it barely proceeds at all.
Metal-catalysed oxidation of methionine is documented across peptide and protein formulations and is why chelators appear in some formulations.
Nothing here is medical advice, and research-use compounds are not approved for human use.
Swirl, never shake. Aggregation is a handling problem more than a time problem.
6The doubling-per-ten-degrees rule is the part I did not know and now use constantly. – tenth_of_a_unit 9 months ago 5Thank you — this is the answer I was looking for. – marta_okonkwo 7 months ago add a comment