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How do I compute the +5 charge state m/z for a peptide of 4207.2 Da?

Asked 4 Feb 2026Modified 2 months agoViewed 9.3k times
This question was marked as a duplicate of How do I compute the +4 charge state m/z for a peptide of 4207.2 Da?Closed 17 Mar 2026. It remains here because the answers below are specific to how it was asked.
21

Conditions: +5 · 4207.2 Da.

I want the working, not the result — I need to be able to redo it with different numbers.

I care about the precision as well as the value — I want to know how many figures are real.

Is my approach right even if my number is wrong?

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Purity as chromatographic area per cent - the fraction of detected material that is your target peak. It says nothing about how much material is…

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PH
askedpetra_hovland35k384 Feb 2026

5 Answers

Accepted answer first, then by votes
26

Accepted answer

m/z = 842.45 at 5+. Electrospray charges a peptide by adding protons, so the observed ion is the neutral mass plus 5 protons, all divided by the charge: (4207.2 + 5 × 1.00728) ÷ 5 = 4212.236 ÷ 5 = 842.45. The proton term is the one people drop, and because it is z protons over z charges it shifts m/z by 1.007 at every charge state — small, and far larger than the mass accuracy of the instrument. The neighbouring charge state sits at 702.21, and seeing the two of them where they belong is better identity evidence than either one alone. Use the average mass against an average-mass calculation and the monoisotopic mass against a monoisotopic one; mixing them costs you a couple of daltons on a peptide this size.

The single most important fact about mass spectrometry for peptides is that it measures only the molecular weight and tells you almost nothing about whether the peak is actually your target.

A mass shift of minus eighteen usually means dehydration or a succinimide intermediate, which is pH-dependent and can be reversible.

The m/z accuracy achievable depends on the mass analyser type — quadrupole gives low accuracy, time-of-flight gives moderate accuracy, and Orbitrap gives high accuracy.

Peptide mapping — enzymatic digestion followed by tandem mass spectrometry — can confirm the primary sequence and is the method of choice when identity is ambiguous.

Worth noting that source contamination is common and silent, so a result that looks too good to be true often is.

Always run a blank between samples and check for carry-over.

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NT
answered · acceptedn_takahashi29k3822 Feb 2026
8The system-suitability data is the part that tells you whether to believe the rest. – Dr_Priya_Raghunathan 9 months ago
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23

It helps to be literal here: tandem mass spectrometry fragments the ions and measures the fragment masses, which provides sequence information and is the best tool for confirming identity.

High-resolution mass spectrometry can distinguish a Lys-containing peptide from an Arg-containing peptide of similar mass because of the isotope difference.

In practice, the baseline noise on a mass spectrum sets the limit of detection, and a weak signal close to the noise is not reliable evidence for the presence of a species.

The limitation is that mass spectrometry tells you the mass and almost nothing else, so it needs to be paired with chromatography or other identity information.

The practical summary: use mass spectrometry for identity, not for purity.

edited 23 Feb 2026 by t_oyelaran — fixed an arithmetic slip in the third paragraph

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TO
answeredt_oyelaran79k4811 Feb 2026
10

To be exact about it, identity confirmation from mass spectrometry means matching the observed m/z to the calculated m/z for your peptide at its known charge states.

For a large peptide with multiple peaks in the mass spectrum, comparing the observed isotope pattern to the calculated pattern is a quick check that the formula matches.

Mechanically, a mass shift of plus one usually means deamidation at asparagine or glutamine, which creates a secondary amine instead of an amide and changes the mass by exactly one.

I would not trust a mass result without a good baseline and a blank injection check.

A correct mass is necessary for identity but not sufficient — you also need the chromatography to confirm it.

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DR
answeredDr_Priya_Raghunathan49k13720 May 2026
7Thank you — this is the answer I was looking for. – lyoph_cake 3 months ago
8Same experience here, different supplier. – pip_okonjo 5 months ago
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9

A mass shift of exactly zero with a shifted retention time points to an isomer — a scrambled disulfide or a racemised residue — which mass spectrometry alone cannot identify.

The charge state distribution depends on the solution pH, the structure of the peptide and the source conditions, so the same peptide can look different under different conditions.

False positives from contamination are common in mass spectrometry work, and running a blank between every sample and a solvent background are standard practice.

If you only pay for one test, pay for quantified content. Purity is the number everyone quotes and content is the number that changes what you do.

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NN
answerednine_point_nine60k14828 Apr 2026
6The distinction between purity and content cannot be repeated often enough here. – rukhsana_iqbal 6 months ago
5Which wavelength was the purity integrated at? It changes the number more than people think. – Dr_Priya_Raghunathan 4 months ago
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8

Two ions with the same nominal mass but different molecular formulae have different exact masses, and only high-resolution mass spectrometry can distinguish them.

A mass shift of minus one hundred and twenty-eight usually means a missing Gln or Lys residue from a synthesis deletion sequence.

In practice: ask for the chromatogram, check the method section, check the lot number against the vial, and set your accept threshold before you see the result rather than after.

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DK
answereddermot_kiely12k1631 May 2026

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