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Does fibrillation of survodutide at 25 °C show up as a loss of content or of purity?

Asked 19 Jan 2025Modified 14 months agoViewed 20k times
6

For reference: fibrillation · survodutide · 25 °C.

I would like the mechanism, because I want to be able to reason about the cases nobody has written about.

I have tried to reason it out from first principles and got to two contradictory conclusions.

What is actually going on here, physically?

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The chemistry of peptide degradation: deamidation, oxidation, hydrolysis, aggregation and fibrillation, and how temperature, pH, ionic strength,…

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ZM
askedzainab_mustafa16k1719 Jan 2025
6Adding for future readers: the certificate should carry the lot number, not just a batch code. – h_villanueva 9 months ago
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5 Answers

Accepted answer first, then by votes
89

Accepted answer

Put another way, a warm arrival is a reason to test, not automatically a reason to discard. Peptide degradation is kinetic — rate multiplied by time — and a few days at thirty degrees in the solid state is a small integral compared to weeks in solution.

Aggregation is the failure mode that reverse-phase HPLC is worst at detecting, because a large soluble aggregate may not elute at all and an insoluble one is filtered out during sample preparation. If your purity result comes back normal but the vial looks hazy, believe the vial. Size-exclusion chromatography is the method that sees this.

Degradation pathway by condition

PathwayDominant whenDetected by
DeamidationSolution, neutral to alkaline pHRP-HPLC, +1 Da on MS
OxidationLight, trace metals, peroxidesRP-HPLC, +16 Da on MS
HydrolysisSolution, extremes of pHRP-HPLC, fragment masses
AggregationAgitation, interfaces, high concentrationSEC, visual haze; often invisible on RP-HPLC
Freeze-concentration damageFreeze-thaw of buffered solutionSEC, loss of recovered content

Freeze-concentration is the mechanism people miss. As ice forms, everything that is not water is excluded into a shrinking unfrozen fraction, so the local concentration of peptide, buffer salts and preservative rises sharply. If the buffer components crystallise at different rates, local pH can shift by more than a unit. That is why a phosphate-buffered solution can behave badly on freezing while an unbuffered one is fine.

Deamidation kinetics for asparagine in peptides are well characterised and strongly sequence-dependent: the residue following the asparagine dominates the rate, with glycine and serine at the n+1 position accelerating it by an order of magnitude relative to bulkier residues. That is why two peptides in the same buffer at the same temperature can have quite different shelf lives.

I would be careful about generalising across sequences. Stability is sequence-specific, and a rule derived from semaglutide will not transfer cleanly to a tri-agonist with different residues in different local environments.

Store solid, store cold, store dry, and reconstitute what you will use rather than what fits in the vial.

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DA
answered · acceptedDr_Yusuf_Adeyemi95k24818 Mar 2025
2This is the first explanation of that which has actually made sense to me. – Dr_Priya_Raghunathan 4 months ago
3Note that the label instructions differ between agents on precisely this point. – mass_shift_18 6 months ago
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76

The honest answer is that published stability data for these specific molecules in a research-grade presentation essentially does not exist, so what you get is extrapolation from the licensed formulations and from general peptide chemistry. That extrapolation is reasonable. It is still extrapolation.

Light matters for specific residues rather than in general. Tryptophan and to a lesser extent tyrosine and methionine are photo-labile; a sequence without them is largely indifferent to ambient light over the timescales in question. Amber glass is cheap insurance rather than a requirement.

Adsorption to the container is a real loss at low concentration. For a peptide at 0.1 mg/mL in an untreated glass vial, single-digit percentage losses to the wall are plausible; at 5 mg/mL it is negligible. This is one of several reasons not to reconstitute to a very dilute working solution and store it.

Where community-submitted samples with known thermal excursions have been tested at Janoshik or Medutest, the recurring finding is that lyophilised material tolerates warm transit far better than intuition suggests, while reconstituted material shipped warm does not. The asymmetry is consistent enough to plan around.

The practical rule is that time and temperature multiply, so shorten whichever one you control.

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NO
answerednkem_obiora46k3829 Mar 2025
37

Freeze-thaw damage happens at the moving ice front, not at the storage temperature. Once the sample is frozen solid and cold, very little is happening. The damage is done during freezing and thawing, which is why the number of cycles matters and the duration of the hold mostly does not.

The temperature dependence is roughly Arrhenius over the range that matters, which in practice means every ten degrees of increase roughly doubles to triples the rate. Ten days at thirty degrees is therefore comparable to something on the order of a month or two at four degrees — bad, but not the catastrophe it feels like when you open a warm parcel.

On the detail: the 28-day figure for a reconstituted preserved vial is microbiological, not chemical. Chemically, a well-behaved peptide at 5 mg/mL at 4 °C will typically lose well under a per cent of content per month. The reason to respect the date is bioburden, and bioburden is a function of how many times you have opened it, not of the calendar.

If the material arrived warm and it was lyophilised, test it and proceed on the result. If it arrived warm and it was in solution, the result is more likely to be interesting than reassuring.

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EV
answeredekaterina_volk16k287 Mar 2025
The timing signature is the useful part. Everything else is confounded. – ilaria_bertone 10 months ago
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30

The lyophilised solid is far more robust than anything anyone says about it, and the solution is far less robust. Most of the confusion in this area comes from advice about one being applied to the other.

For the solid state, residual moisture is the dominant variable. A cake at two per cent water is considerably more stable than the same cake at six per cent, because water is both a reactant in hydrolysis and a plasticiser that lowers the glass transition temperature. This is why a desiccant in the outer packaging is not theatre, and why opening a cold vial in a humid room is a genuine error — you condense water onto the cake.

The single highest-value change most people can make is buying a cheap logging thermometer, because it converts an assumption about their storage into a record.

edited 24 Mar 2025 by j_wierzbicki — expanded the table to cover the lower concentration

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JW
answeredj_wierzbicki45k3824 Feb 2025
24

Degradation is not one process, and which one dominates depends on the condition you are asking about. In solution at refrigerated temperature the rate-limiting pathway is usually deamidation and hydrolysis; at room temperature aggregation overtakes them; frozen, the damage happens during the transitions rather than during the hold.

On re-freezing something that thawed in transit: if it arrived as a lyophilised solid that warmed but never got wet, re-freezing costs you nothing except the thermal cycle. If it arrived as a solution that thawed, re-freezing adds a second transition and therefore a second dose of ice-front shear. The asymmetry is worth internalising.

Minimise transitions rather than minimising temperature. One freeze and one thaw is fine; five is a different question.

edited 5 Jun 2025 by vialroom — added the placebo-arm figures

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VI
answeredvialroom87k14813 May 2025
8Good answer, but the confidence interval in the cited trial is wider than implied. – Dr_Fatima_Belkacem 25 days ago
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