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How do I compute the +3 charge state m/z for a peptide of 4113.6 Da?

Asked 14 Feb 2026Modified 4 months agoViewed 8.4k times
20

What I am working with: +3 · 4113.6 Da.

I have worked this out and I would like someone to find the error, because I suspect there is one.

My working so far, for the record, is below, and I am fairly sure the error is in the unit conversion rather than the algebra.

Where is my error, and what is the correct working?

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TM
askedthabo_maseko20k2714 Feb 2026
6Thank you — the worked example is what makes this usable. – h_pergande 5 months ago
7Related: the same reasoning applies to the counter-ion question. – s_kalniete 6 months ago
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5 Answers

Accepted answer first, then by votes
8

Accepted answer

Tandem mass spectrometry fragments the ions and measures the fragment masses, which provides sequence information and is the best tool for confirming identity.

A mass shift of minus one hundred and twenty-eight usually means a missing Gln or Lys residue from a synthesis deletion sequence.

What each test answers

TestAnswersDoes NOT answer
RP-HPLC, area %What fraction of detected material is the targetHow much target is present
Quantified contentMilligrams of peptide per vialWhat the impurities are
ESI-MS identityWhether the molecular weight matchesPurity, or isomeric substitution
Peptide mappingSequence, localised to a fragmentQuantity
Karl FischerWater content of the solidSolvent content
LAL endotoxinPyrogen load in EU/mgSterility
Sterility testGrowth in defined media over 14 daysEndotoxin, or bioburden count

Worth being precise here: the baseline noise on a mass spectrum sets the limit of detection, and a weak signal close to the noise is not reliable evidence for the presence of a species.

False positives from contamination are common in mass spectrometry work, and running a blank between every sample and a solvent background are standard practice.

One qualification: high-resolution mass spectrometry gives high mass accuracy but low speed, and the reverse is true for low-resolution instruments.

A correct mass is necessary for identity but not sufficient — you also need the chromatography to confirm it.

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DO
answered · acceptedDr_Malik_Osei37k3811 Mar 2026
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20

Start from what electrospray ionisation does: it ionises the peptide without fragmenting it, creating singly or multiply charged species that the mass analyser then separates by their mass-to-charge ratio.

Electrospray ionisation creates multiple charge states of the same peptide — a 4 kDa peptide might appear at +2, +3 and +4 — and all of them must be accounted for in the spectrum.

The relevant detail is that a mass shift of plus sixteen usually means oxidation at methionine or tryptophan, which is common in peptides and often comes from sample handling rather than synthesis failure.

Electrospray ionisation soft-ionisation behaviour is well-characterised and standards exist for m/z calibration and mass accuracy assessment.

The caveat is that a correct mass does not mean the peak is correct — isomers and co-eluting species can have the same m/z.

The practical summary: use mass spectrometry for identity, not for purity.

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TA
answeredtess_amankwah48k382 Apr 2026
6Two of us worked through this independently and arrived here, so it is at least reproducible. – Dr_Yusuf_Adeyemi 10 months ago
5Worth adding that the method section is where the answer usually is. – Dr_Aoife_Brennan 8 months ago
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4

A D-amino-acid substitution has the same molecular weight as the L-form, so mass spectrometry cannot distinguish them without fragmenting the peptide.

For a large peptide with multiple peaks in the mass spectrum, comparing the observed isotope pattern to the calculated pattern is a quick check that the formula matches.

Specifically, a mass shift of plus one usually means deamidation at asparagine or glutamine, which creates a secondary amine instead of an amide and changes the mass by exactly one.

Peptide mapping — enzymatic digestion followed by tandem mass spectrometry — can confirm the primary sequence and is the method of choice when identity is ambiguous.

The limitation is that mass spectrometry tells you the mass and almost nothing else, so it needs to be paired with chromatography or other identity information.

Always run a blank between samples and check for carry-over.

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RC
answeredRP_C1885k15816 Feb 2026
3Small correction: the units in the third paragraph should be micrograms, not milligrams. – low_dead_space 5 months ago
4Do you have a reference for the last claim? Not disputing it, just want to read it. – Dr_Nadia_Farsi 7 months ago
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2

Mass spectrometry is an identity technique, not a purity technique, and conflating the two is a common source of false confidence.

The m/z accuracy achievable depends on the mass analyser type — quadrupole gives low accuracy, time-of-flight gives moderate accuracy, and Orbitrap gives high accuracy.

False positives from contamination are common in mass spectrometry work, and running a blank between every sample and a solvent background are standard practice.

I would not trust a mass result without a good baseline and a blank injection check.

A correct mass is necessary for identity but not sufficient — you also need the chromatography to confirm it.

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AL
answereda_lindgren46k13828 Feb 2026
2

Two ions with the same nominal mass but different molecular formulae have different exact masses, and only high-resolution mass spectrometry can distinguish them.

A mass shift of minus eighteen usually means dehydration or a succinimide intermediate, which is pH-dependent and can be reversible.

Electrospray ionisation soft-ionisation behaviour is well-characterised and standards exist for m/z calibration and mass accuracy assessment.

Worth noting that source contamination is common and silent, so a result that looks too good to be true often is.

The practical summary: use mass spectrometry for identity, not for purity.

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FR
answeredfib4_reader35k3822 Mar 2026

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